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67 lines
1.3 KiB
Go
67 lines
1.3 KiB
Go
package test
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import (
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"strings"
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)
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func Diff(old string, new string) string {
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return strings.Join(diffRec(nil, strings.Split(old, "\n"), strings.Split(new, "\n")), "\n")
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}
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// This is a simple recursive line-by-line diff implementation
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func diffRec(result []string, old []string, new []string) []string {
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o, n, common := lcSubstr(old, new)
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if common == 0 {
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// Everything changed
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for _, line := range old {
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result = append(result, "-"+line)
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}
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for _, line := range new {
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result = append(result, "+"+line)
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}
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} else {
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// Something in the middle stayed the same
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result = diffRec(result, old[:o], new[:n])
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for _, line := range old[o : o+common] {
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result = append(result, " "+line)
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}
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result = diffRec(result, old[o+common:], new[n+common:])
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}
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return result
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}
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// From: https://en.wikipedia.org/wiki/Longest_common_substring_problem
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func lcSubstr(S []string, T []string) (int, int, int) {
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r := len(S)
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n := len(T)
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Lprev := make([]int, n)
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Lnext := make([]int, n)
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z := 0
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retI := 0
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retJ := 0
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for i := 0; i < r; i++ {
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for j := 0; j < n; j++ {
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if S[i] == T[j] {
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if j == 0 {
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Lnext[j] = 1
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} else {
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Lnext[j] = Lprev[j-1] + 1
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}
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if Lnext[j] > z {
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z = Lnext[j]
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retI = i + 1
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retJ = j + 1
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}
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} else {
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Lnext[j] = 0
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}
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}
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Lprev, Lnext = Lnext, Lprev
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}
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return retI - z, retJ - z, z
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}
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